Hi Every one,
fi(x+ei,t+1)= fi(x,t)-[fi(x,t)- fieq(x,t)]/τ, (2)
fieq=ρwi(1+3(ei.u)+4.5(ei.u)2-1.5u2), (3)
ν=(2τ-1)/6. (4)
On above equations someone comments:
Dimension in Eq.(3) and Eq(4) are wrong. For example, in Eq(4), viscosity \nu should has identical dimension as \tau. On the other hand, from Eq.(2), it seems \tau is a non-dimensional parameter. Hence \nu seems a non-dimensional parameter. This is not correct.
What will be the possible answer of the above question.
Thanks