Hi Every one,

fi(x+ei,t+1)= fi(x,t)-[fi(x,t)- fieq(x,t)]/τ, (2)

fieq=ρwi(1+3(ei.u)+4.5(ei.u)2-1.5u2), (3)

ν=(2τ-1)/6. (4)

On above equations someone comments:

Dimension in Eq.(3) and Eq(4) are wrong. For example, in Eq(4), viscosity \nu should has identical dimension as \tau. On the other hand, from Eq.(2), it seems \tau is a non-dimensional parameter. Hence \nu seems a non-dimensional parameter. This is not correct.

What will be the possible answer of the above question.

Thanks