Code of flow around a cylinder(Zou/He boundary)_conservation problem

Hi, everyone
I want to simulate the flow around a cylinder. The Inlet adopts velocity boundary condition, Outlet adopts pressure boundary condition, Wall boundary adopts bounce-back condition. I found a sample Matlab code about this problem on the internet. But after checking the total mass and total momentum in x and y direction, I found that they are not conserved. So I think there may be something wrong with the code. Could anyone help me check this? Thank you very much.


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
clear

% GENERAL FLOW CONSTANTS
lx     = 400;      % number of cells in x-direction
ly     = 100;      % number of cells in y-direction
obst_x = lx/5+1;   % position of the cylinder; (exact
obst_y = ly/2+3;   % y-symmetry is avoided)
obst_r = ly/10+1;  % radius of the cylinder
uMax   = 0.1;      % maximum velocity of Poiseuille inflow
Re     = 100;      % Reynolds number
nu     = uMax * 2.*obst_r / Re;  % kinematic viscosity
omega  = 1. / (3*nu+1./2.);      % relaxation parameter
maxT   = 1001;  % total number of iterations
tPlot  = 50;      % cycles
total_mass = zeros(maxT,2);
total_momentum_x = zeros(maxT,2);
total_momentum_y = zeros(maxT,2);

% D2Q9 LATTICE CONSTANTS
t  = [4/9, 1/9,1/9,1/9,1/9, 1/36,1/36,1/36,1/36];
cx = [  0,   1,  0, -1,  0,    1,  -1,  -1,   1];
cy = [  0,   0,  1,  0, -1,    1,   1,  -1,  -1];
opp = [ 1,   4,  5,  2,  3,    8,   9,   6,   7];
col = [2:(ly-1)];
in  = 1;   % position of inlet
out = lx;  % position of outlet

[y,x] = meshgrid(1:ly,1:lx); % get coordinate of matrix indices
  
obst = ...                   % Location of cylinder
    (x-obst_x).^2 + (y-obst_y).^2 <= obst_r.^2;
obst(:,[1,ly]) = 1;    % Location of top/bottom boundary
bbRegion = find(obst); % Boolean mask for bounce-back cells

% INITIAL CONDITION: Poiseuille profile at equilibrium
L = ly-2; y_phys = y-1.5;
ux = 4 * uMax / (L*L) * (y_phys.*L-y_phys.*y_phys);
% for i=2:lx
%     for j=1:ly
%         ux(i,j) = 0;
%     end
% end
uy = zeros(lx,ly);
rho = 1;
for i=1:9
    cu = 3*(cx(i)*ux+cy(i)*uy);
    fIn(i,:,:) = rho .* t(i) .* ...
                   ( 1 + cu + 1/2*(cu.*cu) - 3/2*(ux.^2+uy.^2) );
end

% MAIN LOOP (TIME CYCLES)
for cycle = 1:maxT

    % MACROSCOPIC VARIABLES
    rho = sum(fIn);
    ux  = reshape ( (cx * reshape(fIn,9,lx*ly)), 1,lx,ly) ./rho;
    uy  = reshape ( (cy * reshape(fIn,9,lx*ly)), 1,lx,ly) ./rho;
    total_mass(cycle,1) = cycle;
    total_mass(cycle,2) = sum(sum(rho));
    total_momentum_x(cycle,1) = cycle;
    total_momentum_x(cycle,2) = sum(sum(rho.*ux));
    total_momentum_y(cycle,1) = cycle;
    total_momentum_y(cycle,2) = sum(sum(rho.*uy));
    %if (total_mass(cycle,2)-total_mass(1,2))>200, break, end
   
    % MACROSCOPIC (DIRICHLET) BOUNDARY CONDITIONS
      % Inlet: Poiseuille profile
    y_phys = col-1.5;
    ux(:,in,col) = 4 * uMax / (L*L) * (y_phys.*L-y_phys.*y_phys);
    uy(:,in,col) = 0;
    rho(:,in,col) = 1 ./ (1-ux(:,in,col)) .* ( ...
        sum(fIn([1,3,5],in,col)) + 2*sum(fIn([4,7,8],in,col)) );
      % Outlet: Constant pressure
    rho(:,out,col) = 1;
    ux(:,out,col) = -1 + 1 ./ (rho(:,out,col)) .* ( ...
        sum(fIn([1,3,5],out,col)) + 2*sum(fIn([2,6,9],out,col)) );
    uy(:,out,col)  = 0;

    % MICROSCOPIC BOUNDARY CONDITIONS: INLET (Zou/He BC)
    fIn(2,in,col) = fIn(4,in,col) + 2/3*rho(:,in,col).*ux(:,in,col); 
    fIn(6,in,col) = fIn(8,in,col) + 1/2*(fIn(5,in,col)-fIn(3,in,col)) ... 
                                    + 1/2*rho(:,in,col).*uy(:,in,col) ...
                                    + 1/6*rho(:,in,col).*ux(:,in,col); 
    fIn(9,in,col) = fIn(7,in,col) + 1/2*(fIn(3,in,col)-fIn(5,in,col)) ... 
                                    - 1/2*rho(:,in,col).*uy(:,in,col) ...
                                    + 1/6*rho(:,in,col).*ux(:,in,col); 

    % MICROSCOPIC BOUNDARY CONDITIONS: OUTLET (Zou/He BC)
    fIn(4,out,col) = fIn(2,out,col) - 2/3*rho(:,out,col).*ux(:,out,col); 
    fIn(8,out,col) = fIn(6,out,col) + 1/2*(fIn(3,out,col)-fIn(5,out,col)) ... 
                                      - 1/2*rho(:,out,col).*uy(:,out,col) ...
                                      - 1/6*rho(:,out,col).*ux(:,out,col); 
    fIn(7,out,col) = fIn(9,out,col) + 1/2*(fIn(5,out,col)-fIn(3,out,col)) ... 
                                      + 1/2*rho(:,out,col).*uy(:,out,col) ...
                                      - 1/6*rho(:,out,col).*ux(:,out,col); 

    % COLLISION STEP
    for i=1:9
       cu = 3*(cx(i)*ux+cy(i)*uy);
       fEq(i,:,:)  = rho .* t(i) .* ...
                       ( 1 + cu + 1/2*(cu.*cu)  - 3/2*(ux.^2+uy.^2) );
       fOut(i,:,:) = fIn(i,:,:) - omega .* (fIn(i,:,:)-fEq(i,:,:));
    end

    % OBSTACLE (BOUNCE-BACK)
    for i=1:9
         fOut(i,bbRegion) = fIn(opp(i),bbRegion);
    end

    % STREAMING STEP
    for i=1:9
       fIn(i,:,:) = circshift(fOut(i,:,:), [0,cx(i),cy(i)]);
    end

    % VISUALIZATION
    if (mod(cycle,tPlot)==1)
        u = reshape(sqrt(ux.^2+uy.^2),lx,ly);
        u(bbRegion) = nan;
        imagesc(u');
        colorbar
        title(num2str(cycle));
        axis equal off; drawnow
    end
end

dear Daniel,

Did you try for instance a set of inlet/outlet BC that work? I mean, are you 100% sure that you have the problem in this routine?

Could be the wall bounceback, do you have a significant mass decayment? Do you use parabolic flow? Does it conserve its shape, disregarding the obstacle? Have oyur tried without obstacle first? Do you move along a reasonable relaxation time?

I am a fortran user so I am not really understanding everything of the matlab code. But I asume that if you have found it as a sample on the net it is strange that it does not work.

Hope you solve this issue

Puigar